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It’s no longer Koha’s b-day in my time zone, but it’s still Koha-day in most time zones west of here, so …
MORE DOUBLE DACTYLS FOR KOHA! YAYZ ^_^
Seriously, the double dactyl is the most demented form of poetry ever … hence, perfect for Koha. ^_^
Futari wa NS
Futari hitori,
Hikaru, Kirari
Team up to try to dis-
Prove Gauss’s rule.
Finding no monopole,
Sadly they figure that
Ferromagnetically
Poles must be dual.
Ramutara
Ramutaarattattan!
World-weary Koha-chan
Cuts ‘cross Kamchatka to
Kolkata … more!
Finished with traveling,
Koha now looks for a
Nongeographical
Place to explore.
Sansan GOGO
DNA → RNA:
Misinformed MilkyWay
Err in directing us
Which way to go.
5-prime to 3-prime’s how
Nucleotides link up
Ribonucleically
All in a row.
Olala*
Olala olala,
Mademoiselle Kusumi
A commencé à chan-
Ter en français.
Cependant, tout le monde
Trouvait son accès de
« Francocacophonie »
Vraiment mauvais.
* A rough English translation that loses all of the delicious rhyming tonguetwistery of the French:
Olala olala,
Miss Kusumi
Started to sing
In French.
However, all the world
Found her outburst of
“Francocacophonie”
Truly bad.
Yayz! I wanted to do 16 double dactyls in honor of Koha’s turning 16, but since double dactyls do double duty, so to speak, 8 should be enough. ^.^
I’ll probably have more double dactyls to post in the near future, though….
As I’ve mentioned elsewhere, while I love compiling rankings of works released by Hello! Project, I refuse to give a subjective ranking of individual people, for various reasons. But Paul Thomas’s new poll is just so shiny I couldn’t resist…
So here is my objective ranking of Morning Musume, Berryz Koubou, and ºC-ute, using criteria that (I assume) no fan actually uses, consciously or not, to determine their favorites, though the near-perfect (except Kamei) spectral order of MoMusu is rather interesting and makes me suspect someone on the inside might be using a similar criterion to assign costume colors…
Sure, it might be a coincidence, but really, the probability of at least n – 1 out of n elements randomly appearing in a specified order is 
* I leave the proof of this formula as an exercise for the reader.
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